ee01003 Posted April 16, 2008 Share Posted April 16, 2008 hi, i am a newbie in the cctv systems. i have some problems in calculating the storage needs in a cctv system. i know that the factors that i have to considered when calculating storage needs are: -number of cameras -number of hours per day, that the camera will be recording -how long the data must be stored - frame rate , compression, image quality and complexity for the bellow exemple (per example) : if i have 1 camera whit: resolution= 640 * 480 frames per second=25 period of storage= 8 hours compression = MJPEG (50) i know that i have to use this formula (FOR 1 CAMERA): required storage space=image size* frames per second * period of request my principal question is how i can calculating the image size? and how resolution and compression influences the image size? and for the case that i use the m4peg? how can i know the storage requeried ? how can i know the bandwidth requeried ? can anybody help me? best regards Link to comment Share on other sites More sharing options...
breff Posted April 16, 2008 Share Posted April 16, 2008 I would allow 15-20gb per camera for 8 hours@25fps although I estimate about 19gb. attached is a storage chart from dedicated micros, they say 25k equates to better than 400 tv lines. storagechart.pdf The opinions I express are mine and are usually correct! (Except when I'm wrong)(which I'm not) Link to comment Share on other sites More sharing options...
ee01003 Posted April 17, 2008 Author Share Posted April 17, 2008 thanks for your help... i have seen your attached, but i don Link to comment Share on other sites More sharing options...
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