cadgey Posted June 15, 2008 Posted June 15, 2008 Hi I have installed a Galaxy G2-20 system, with a mixture of wired & wireless PIR's and door contacts. I decided to add a smoke alarm to the system, and have purchased one that has contacts for +ve, -ve, and then 2 x alarm. I realise that I need to wire in the +12v, and the 0v, and also need to wire a 1k resistor in-line and across the alarm contacts, but am struggling to work out the final connections. No doubt this is completely simple, but if anyone could point me the right way I would really appreciate it - it really isn't clear how to wire up this sort of connector in the manual, and the door contacts I bought were already wired with resistors, and didn't have power running to them either. Currently have connectors: 1 - 12v 2 - 0v 3 - Alarm - i have the single "zone" wire form the panel coming into this with an in-line 1k resistor, then another resistor wired from 3-4 4 - Alarm - where fo I join this back to - the 0v? And on the panel: a) 12v - connected to 1 B) 0v - connected to 2 c) Zone Any help would be appreciated. Cadgey
djandysp Posted June 15, 2008 Posted June 15, 2008 I always thought you needed 2 x 1k resistors on a galaxy unless youve got a few devices on one circuit
james.wilson Posted June 15, 2008 Posted June 15, 2008 yes you will need 2 resistors else it will show a short circuit in diagnostics securitywarehouse Security Supplies from Security Warehouse Trade Members please contact us for your TSI vetted trade discount.
cadgey Posted June 15, 2008 Author Posted June 15, 2008 Hi Thanks for the response - i do have 2 resistors - one in-line, before the trigger switch and one bridginging the trigger switch. On activation it will (I believe) switch from 2k to 1k. This is how it is rigged on the PIR's, but I just can't work out how to wire the circuit back to the zone. In my logic, there should be a +12v and a 0v, and then 2 connections to the alarm trigger. But there is only one - the zone connection. Confused!
Guest RJBsec Posted June 15, 2008 Posted June 15, 2008 Look at the zone terminals on the circuit board, each zone has one terminal and one shared terminal.
cadgey Posted June 15, 2008 Author Posted June 15, 2008 Look at the zone terminals on the circuit board, each zone has one terminal and one shared terminal. Thanks RJB - my assumption, therefore is that I wire it back to the 0v? i.e. 12v panel to 12v unit standalone 0v panel to to 0V unit Zone on panel -> 1k resistor -> "alarm 1" on unit "Alarm 1" on unit connected to "alarm 2" on unit by 1k resistor Alarm 2 on unit connected back to 0v Does that make any sense? Appreciate the help.
Gopher Posted June 16, 2008 Posted June 16, 2008 Thanks RJB - my assumption, therefore is that I wire it back to the 0v?i.e. 12v panel to 12v unit standalone 0v panel to to 0V unit Zone on panel -> 1k resistor -> "alarm 1" on unit "Alarm 1" on unit connected to "alarm 2" on unit by 1k resistor Alarm 2 on unit connected back to 0v Does that make any sense? Appreciate the help. alarm 2 goes back to the panel in the zone common (0v) not the actual -ve supply. Intruder / CCTV / Access Control Technical Support Personal Subscriber to the "K.I.S.S" principle, that's Keep It Simple Stupid, are you?
cadgey Posted June 16, 2008 Author Posted June 16, 2008 Doh! Thanks very much - just worked out where I was going wrong from your post. Been too long since install and getting my 0v's confused! Thanks to all for help - much appreciated. Cadgey
Gopher Posted June 17, 2008 Posted June 17, 2008 No problem, glad you got it sorted out. Intruder / CCTV / Access Control Technical Support Personal Subscriber to the "K.I.S.S" principle, that's Keep It Simple Stupid, are you?
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