sparky999 Posted August 30, 2019 Share Posted August 30, 2019 Cmin=1.25(T1xI1+T2xI2x1.75) which is the calculation in BS 5839-6:2019 which is easier in my view as I hate doing division. the T2 is 0.5 which is the same as dividing by 2 . T1 = 24hours l1 = quiescent load T2 = 30 minutes in alarm l2 = alarm load 1.75 = derating factor Quote Peter Robinson Freelance M:07889038650 Link to comment Share on other sites More sharing options...
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